3[z-(5z+10)+6]=2(z+1)

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Solution for 3[z-(5z+10)+6]=2(z+1) equation:


Simplifying
3[z + -1(5z + 10) + 6] = 2(z + 1)

Reorder the terms:
3[z + -1(10 + 5z) + 6] = 2(z + 1)
3[z + (10 * -1 + 5z * -1) + 6] = 2(z + 1)
3[z + (-10 + -5z) + 6] = 2(z + 1)

Reorder the terms:
3[-10 + 6 + z + -5z] = 2(z + 1)

Combine like terms: -10 + 6 = -4
3[-4 + z + -5z] = 2(z + 1)

Combine like terms: z + -5z = -4z
3[-4 + -4z] = 2(z + 1)
[-4 * 3 + -4z * 3] = 2(z + 1)
[-12 + -12z] = 2(z + 1)

Reorder the terms:
-12 + -12z = 2(1 + z)
-12 + -12z = (1 * 2 + z * 2)
-12 + -12z = (2 + 2z)

Solving
-12 + -12z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-12 + -12z + -2z = 2 + 2z + -2z

Combine like terms: -12z + -2z = -14z
-12 + -14z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-12 + -14z = 2 + 0
-12 + -14z = 2

Add '12' to each side of the equation.
-12 + 12 + -14z = 2 + 12

Combine like terms: -12 + 12 = 0
0 + -14z = 2 + 12
-14z = 2 + 12

Combine like terms: 2 + 12 = 14
-14z = 14

Divide each side by '-14'.
z = -1

Simplifying
z = -1

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